Returned 36 matches (37 formulae, 8 docs)
    Lookup 0.241 ms, Re-ranking 148.061 ms
    Found 56 tuple postings, 37 formulae, 8 documents
[ formulas ] [ documents ] [ documents-by-formula ]

Doc 1
1.0000
0.0000
5.0000
8.6562
testing/wikipedia/v3/21658.html
𝐉 𝐓 𝐖 𝚫 𝐲
( 𝐉 𝐓 𝐖𝐉 ) 𝚫 𝜷 = 𝐉 𝐓 𝐖 𝚫 𝐲 .
λ 𝐈 𝐉 𝐓 𝐖𝐉 ,  𝚫 𝜷 1 / λ 𝐉 𝐓 𝐖 𝚫 𝐲 .
( 𝐉 𝐓 𝐉 ) 𝚫 𝜷 = 𝐉 𝐓 𝚫 𝐲 .
𝐑 𝐧 𝚫 𝜷 = ( 𝐐 𝐓 𝚫 𝐲 ) 𝐧 .
𝚫 β = 𝐕 𝚺 - 𝟏 ( 𝐔 𝐓 𝚫 𝐲 ) n .
𝐐 𝐓 𝐫 = 𝐐 𝐓 𝚫 𝐲 - 𝐑 𝚫 𝜷 = [ ( 𝐐 𝐓 𝚫 𝐲 - 𝐑 𝚫 𝜷 ) n ( 𝐐 𝐓 𝚫 𝐲 ) m - n ]
( 𝐉 𝐓 𝐖𝐉 + λ 𝐈 ) 𝚫 𝜷 = ( 𝐉 𝐓 𝐖 ) 𝚫 𝐲
1 / trace ( 𝐉 𝐓 𝐖𝐉 ) - 𝟏
𝐫 = 𝚫 𝐲 - 𝐉 𝚫 𝜷 .
( 𝐉 𝐓 𝐖𝐉 ) 𝚫 𝜷 = ( 𝐉 𝐓 𝐖 ) 𝚫 𝐲
𝐉 𝐓 𝐉
Doc 2
1.0000
-8.0000
5.0000
1.7742
testing/wikipedia/v3/02082.html
( 𝐉 𝐓 𝐖𝐉 ) 𝚫 β = 𝐉 𝐓 𝐖 𝚫 𝐲 .
( 𝐉 𝐓 𝐉 ) 𝚫 𝜷 = 𝐉 𝐓 𝚫 𝐲 .

Doc 3
1.0000
-11.0000
3.0000
2.5455
testing/wikipedia/v3/07126.html
𝐗 𝐓 𝐌 - 𝟏 𝐗 𝚫 𝜷 = 𝐗 𝐓 𝐌 - 𝟏 𝚫 𝐲
𝐉 𝐓 𝐌 - 𝟏 𝐉 𝚫 𝜷 = 𝐉 𝐓 𝐌 - 𝟏 𝚫 𝐲 .
𝐅 = 𝚫 𝐲 - 𝐟 𝐫 𝐱 𝐫 𝐱 - 𝐟 𝐫 𝐲 𝐫 𝐲 - 𝐗 𝚫 𝜷 = 𝟎
Doc 4
0.7742
-13.0000
2.0000
2.7882
testing/wikipedia/v3/09762.html
𝐚 = ( 𝐉 𝐓 𝐖𝐉 ) - 1 𝐉 𝐓 𝐖𝐲    W i , i 1
𝐚 = ( 𝐉 𝐓 𝐉 ) - 𝟏 𝐉 𝐓 𝐲
𝐉 𝐓 𝐉 e v e n = ( 5 10 10 34 ) and 𝐉 𝐓 𝐉 o d d = ( 10 34 34 130 )
𝐂 = ( 𝐉 𝐓 𝐉 ) - 𝟏 𝐉 𝐓
( 𝐉 𝐓 𝐉 ) even - 1 = 1 70 ( 34 - 10 - 10 5 ) and ( 𝐉 𝐓 𝐉 ) odd - 1 = 1 144 ( 130 - 34 - 34 10 )
𝐉 𝐓 𝐉 = ( m z z 2 z 3 z z 2 z 3 z 4 z 2 z 3 z 4 z 5 z 3 z 4 z 5 z 6 ) = ( m 0 z 2 0 0 z 2 0 z 4 z 2 0 z 4 0 0 z 4 0 z 6 ) = ( 5 0 10 0 0 10 0 34 10 0 34 0 0 34 0 130 )
Doc 5
0.7742
-19.0000
3.0000
4.7322
testing/wikipedia/v3/17016.html
𝚺 𝐩 = ( 𝐉 𝐓 𝐖𝐉 ) - 𝟏 𝐉 𝐓 𝐖 𝚺 𝐲 𝐖 𝐓 𝐉 ( 𝐉 𝐓 𝐖𝐉 ) - 𝟏
( 𝐉 𝐓 𝐖𝐉 + λ 𝐈 ) δ 𝐩 = 𝐉 𝐓 𝐖𝐫
𝚺 𝐩 = ( 𝐉 𝐓 𝐖𝐉 ) - 𝟏
( 𝐉 𝐓 𝐖𝐉 ) δ 𝐩 = 𝐉 𝐓 𝐖𝐫
𝐩 = ( 𝐉 𝐓 𝐖𝐉 ) - 𝟏 𝐉 𝐓 𝐖𝐲 𝐨𝐛𝐬
𝐖 = 𝐈 , 𝐩 = ( 𝐉 𝐓 𝐉 ) - 𝟏 𝐉 𝐓 𝐲
𝐫 = 𝐲 obs - 𝐉 ( 𝐉 𝐓 𝐓 ) - 𝟏 𝐉 𝐓 𝐲 obs
𝐉 ( 𝐉 𝐓 𝐓 ) - 𝟏 𝐉
𝚺 𝐩 = 𝐔 𝐧 𝐝 - 𝐧 𝐩 ( 𝐉 𝐓 𝐉 ) - 𝟏
Doc 6
0.5455
-9.0000
1.0000
0.8531
testing/wikipedia/v3/07749.html
( 𝐉 𝐓 𝐉 + λ 𝐃 ) Δ = 𝐉 T 𝐫
𝐉 𝐫 𝐓 𝐉 𝐫

Doc 7
0.5455
-10.0000
2.0000
0.5455
testing/wikipedia/v3/07373.html
𝜷 ^ ( 𝐉 𝐓 𝐉 ) - 𝟏 𝐉 𝐓 𝐲 .

Doc 8
0.3529
-14.0000
2.0000
1.0136
testing/wikipedia/v3/06881.html
( 𝐉 𝐓 𝐉 + λ 𝐈 ) 𝜹 = 𝐉 𝐓 [ 𝐲 - 𝐟 ( 𝜷 ) ]
( 𝐉 𝐓 𝐉 + λ 𝐝𝐢𝐚𝐠 ( 𝐉 𝐓 𝐉 ) ) 𝜹 = 𝐉 𝐓 [ 𝐲 - 𝐟 ( 𝜷 ) ]
( 𝐉 𝐓 𝐉 ) 𝜹 = 𝐉 𝐓 [ 𝐲 - 𝐟 ( 𝜷 ) ]