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Does there exist a continuous map $f : [0, 1] \to [0, 1] \times [0, 1]$ such that the pre-image of any point of the square $[0, 1] \times [0, 1]$ contains precisely two points of the interval $[0, 1]$?

I guess the answer is no, but i have no idea how to consider this, even how to start? Anyone can help? Thanks!

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No. If the preimage of a point is $\{x_1,x_2\}$ with $x_1

Further hint: you also need to use that $[0,1]$ is compact.