You need to interpolate between those values and extrapolate beyond them.
One possibility is that what you actually have is a uniform distribution on the interval $[14,64]$ in which case the mean would be $\dfrac{14+64}{2}=39$ and variance $\dfrac{(64-14)^2}{12}\approx 208.3333$.
In most cases life will not be as simple as this, and you will need numerical methods. You have incomplete data, so suppose your $X_i$ finish with 62.5 67.5 and your $Y_i$ finish with 0.97 1. Then you can estimate, by putting the probability at the centre of each interval, the first moment with $$\sum_i (Y_i-Y_{i-1})\left(\frac{X_{i-1}+X_i}{2}\right)$$ which in this case would be $39$, and estimate the second moment with $$\sum_i (Y_i-Y_{i-1})\left(\frac{X_{i-1}+X_i}{2}\right)^2$$ which in this case would be $1732.5$, giving an estimate of the variance of $1732.5-39^2=211.5.$