Is this solvable? I think not, I think something is missing.
Am i wrong?
If 4a + b = 3 then 20a + 5 = ?
a. 15
b. 1/4
c. 4/3
d. 3/4
Is this solvable? I think not, I think something is missing.
Am i wrong?
If 4a + b = 3 then 20a + 5 = ?
a. 15
b. 1/4
c. 4/3
d. 3/4
You are quite correct: something has to be missing. No matter what value you give $a$, there is a value of $b$ that makes the first equation true, so $20a+5$ is indeterminate.
From the answers given, it’s clear that the second expression was supposed to be $20a+5b$; since this is $5(4a+b)$, the intended correct answer must be $15$.
You got 1 equation with 2 unknowns and you're trying to find the first one (finding 20a+5 requires a). Therefore it's unsolvable.