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What is the completion of a metric space $(\mathbb{Q}, |\ \ |)$?

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    Do you know why $\mathbb{Q}$ is not complete?2012-06-10
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    it's $\mathbb{R}$.2012-06-10
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    I'm pretty sure if you just looked this up on Wikipedia you'd find it. If you're having trouble with that definition, feel free to ask about the details.2012-06-10
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    @Glougloubarbaki : It depends on what "$| \, |$" means. It can be $\mathbb R$ or $\mathbb Q_p$, the $p$-adics. It all depends on the chosen metric.2012-06-10
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    @david : Perhaps you should precise what "$| \, \, |$" means. If it means the standard absolute value (the geometric distance between two points), then your completion you're looking for is $\mathbb R$, because it can precisely be defined like this. If you want details, as benmachine said, just ask.2012-06-10
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    is the usual metric, I have problems to show the isomorphism2012-06-10
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    @david : What isomorphism? Between $\mathbb R$ and the completion? Are you thinking about an isomorphism of metric spaces? (i.e. an isometry)2012-06-10
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    "a problem to show the isomorphism" ... OK, on one side is the completion of $\mathbb Q$, on the other side is $\mathbb R$ ... so we need a definition of $\mathbb R$ in order to help you.2012-06-10

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A metric space $X$ is complete if every Cauchy sequence $a_n \in X$ converges to an element $a \in X$.

The completion of $X$ therefore is the metric space $\bar X$, that contains all elements of $X$, plus the limits of all possible cauchy sequences in $X$ equipped with the same metric as $X$. There is no straight forward way in finding the completion of a Metric space.

In your particular case it was already mentioned in the comments, that the completion of $\mathbb{Q}$ with the canonical metric is $\mathbb{R}$ with the canonical metric.

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    help me please in the proof2012-06-10
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If $X$ is a metric space, then the completion of $X$, denote it by $X_c$, is the smallest complete metric space containing $X$ as a subspace. That is, if $Y$ is complete and contains $X$ as a subspace, then $Y$ also contains $X_c$ as a subspace.

If $Y$ is complete, then a subspace of $Y$ is complete if and only if it is closed in $Y$.

Assuming that you have proved these two things, you can use them to find that the completion of $(\mathbb{Q}, |\cdot|)$ is $(\mathbb{R}, |\cdot|)$. What must a complete subspace of $\mathbb{R}$ containing $\mathbb{Q}$ be?

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    help me please in the proof2012-06-10