Hi I'm trying to figure out how to calculate the coordinates of a dot at a certain percentage point on an arc. Let's say the dot starts at (800, 300), the half-way points is (400, 0) and the end point is (0, 300). Let's say I want to calculate where the dot will be after traveling 25% of the arc. I'm really clueless where to start on this, thanks for your help.
Calculating points in an arc
2
$\begingroup$
geometry
-
0Is this an arc of a circle? – 2012-09-29
-
0Well its shape would fit the edge of a circle, but how big that circle would be I have no idea. Imagine the sun rises at (800, 300), the highest point it reaches is (400, 0), and it sets at (0, 300). How would I calculate its coordinates when it's risen 50% (half-way between (800, 300) and (400, 0)) – 2012-09-29
-
0There are infinitely many parabolic arcs that go through those three points. Do you have any more information about the function for the arc? – 2012-09-29
-
1Oh yes I see now >_<. Stupid me, well I will just make a giant circle and chop the top off and use that as my arc then. I can calculate that then since I know the radius, thanks lol. :) – 2012-09-29
1 Answers
0
It appears from the comments that you are happy to take the arc to be an arc of a circle. There is conflicting evidence as to whether you can work out what the circle is, so I'll discuss that. If the radius of the circle is $r$, then, by symmetry, the center of the circle is at $C=(400,r)$. We must have $$(400)^2+(r-300)^2=r^2,$$ an equation which is easy to solve to get $r$.
Now you want the point halfway from $A=(800,300)$ to $B=(400,0)$. You have to find the angle $\theta=\angle ACB$, then you have to bisect it, then you have to find where the bisector meets the arc, that is, you want the point $D$ on the arc for which $\angle ACD=\theta/2$. Come back if you have any trouble carrying out these calculations.