One of the roots of the equation$2000x^6 + 100x^5 + 10x^3 + x - 2=0$ is in the form of $(\frac{\sqrt m+n}{r})$ . Find m,n,r. This is a ques in my sequence and progression sheet so please tell a solution related to it. I tried it several times but not getting a way to solve it.. plzz help. Thank you.
Sequence and progression
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$\begingroup$
linear-algebra
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1$(\frac{\sqrt{m}-n}{r})$ is probably a root too & there is probably a nice quadratic factor ... – 2017-02-28
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0@DietrichBurde You were about 1 minute ahead of me ... good answer ! – 2017-02-28
1 Answers
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Hint: We have $$ 2000x^6 + 100x^5 + 10x^3 + x - 2=(100x^4 + 10x^2 + 1)(20x^2 + x - 2), $$ and the second factor has solutions of the required form. I am sorry, but I don't know what your progression sheet is; anyway $(m,n,r)=(161,-1,40)$.
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0Thnx brother... But answer given here is – 2017-02-28
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0Ohh sry.. got it... Thnx – 2017-02-28
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0Plzz tell how it cliked in your mind how to make factors.. i often got stuck in these type of problems... – 2017-02-28