What could be the limit of this expression? $$\lim_{N \to \infty} \dfrac{\log(N)^3}{\pi N}$$
when we have only $\log(N)$ it gives zero by using a bound, but what can we say about $\log(N)^3$ ?
What could be the limit of this expression? $$\lim_{N \to \infty} \dfrac{\log(N)^3}{\pi N}$$
when we have only $\log(N)$ it gives zero by using a bound, but what can we say about $\log(N)^3$ ?
tl;dr: It is the same.
You can rewrite (ignoring the $\pi$, which is not changing the result) $$ \frac{(\log N)^3}{N} = \left( \frac{\log N}{N^{1/3}}\right)^3 = \left( \frac{3\log (N^{1/3})}{N^{1/3}}\right)^3 = 27\left( \frac{\log (N^{1/3})}{N^{1/3}}\right)^3 $$ and since $N^{1/3}\xrightarrow[N\to\infty]{}\infty$, we have that $$ \frac{\log (N^{1/3})}{N^{1/3}}\xrightarrow[N\to\infty]{}0 $$ using the limit you already know. By continuity of $x\mapsto x^3$, we then have $$ \frac{(\log N)^3}{N} \xrightarrow[N\to\infty]{}0^3 = 0. $$
Note: This holds for any (constant) exponent: for every fixed $k\in\mathbb{R}$, $$ \frac{(\log N)^k}{N} \xrightarrow[N\to\infty]{}0. $$