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Does the function $f: \mathbb{R} \rightarrow \mathbb{R}$ exist if

  1. $f(1) = 1$ and $f(-1) = -1$, and
  2. $|f(x) - f(y)| \leq |x-y|^{3/2}$ for all $x,y \in \mathbb{R}$.

1 Answers 1

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Hint:

\begin{align} \left|\frac{f(x)-f(y)}{x-y}-0\right| \leq |x-y|^{1/2} \end{align} which means $f$ is differentiable. So what is the derivative at every point?