Am trying to find the coordinates of the points where the tangent is horizontal
on this equation:
y = 4 + (x-5)^6
I have worked it to this point with the chain rule
y'=6(x-5)^5
however am unable to find the x coordinates.
Any help appreciated thanks =)
Finding coordinates with functions that have high powers
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$\begingroup$
derivatives
chain-rule
tangent-line
1 Answers
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we have $$y'=6(x-5)^5=0$$ if $$x=5$$ to find the find the Point we get $$f(5)=4$$
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0Ah okay, so even if there's a large power the null point law still only applies once sorry just get confused with this. – 2017-02-27