I'm asked to find a 2nd order linear homogeneous differential equation with constant coefficients, given a solution.
This is my work:

I'm asked to find a 2nd order linear homogeneous differential equation with constant coefficients, given a solution.
This is my work:

Given that problem, I would notice that the solution is of the form $y=e^{ax}(c_{1}\sin bx + c_{2}\cos bx)$
Where $a\pm bi$ are the roots to the characteristic equation of the 2nd order ODE, with $a = -1, b = 3$.
So if our 2nd order ODE is of the form $y'' + Ay' + C = 0$, then it is simple to prove that:
$(-1+3i)(-1-3i) = C \Rightarrow C = 10$
$-(-1+3i -1 -3i) = A \Rightarrow A = 2$
Then the second order ODE is:
$y'' +2y'+10=0$