Is $$2^{\log n+ 1 }= 2\times 2^{\log n}?$$
Because when we add the powers in $2 ^{\log n}\times 2^1$, we get $2^{\log n+ 1} $.
Am I right ?Thanks in advance.
What is $2^{\log (n) + 1} $?
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algebra-precalculus
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0if log has base $2$ then $2^{log n} = n$. – 2017-02-26
1 Answers
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Yes, you are right.
It is obvious that $$a^{\alpha + \beta} = a^{\alpha}\times a^{\beta} $$ (On a side note, think when it is not true.)
Hope it helps.