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A real number may have a complex $n^{\text{th}}$ root. Can a non-real complex number have a real $n^{\text{th}}$ root?

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    By 'non real complex number' do you mean an imaginary number? Also, whilst I think I understand what you're trying to say, the question as you've presented it makes no sense – 2017-02-25
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    @mrnovice how does the question make *no sense* if you think you've understood what they're trying to say? – 2017-02-25
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    That's a fair point – 2017-02-25

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Can a nonreal complex number have a real nth root?

Hint:  can a real number raised to the $n^{th}$ power be a non-real complex number?