1
$\begingroup$

How would you go about integrating this?

$ \int_{-\infty}^{\infty} \, e^{-ax^2} e^{-b(c-x^2)} dx$

Where a,b,c are constants.

Don't really know where to begin

  • 0
    Write your integrand function as $e^{-bc} e^{-(a-b)x^2}$.2017-02-24
  • 0
    And if $a-b>0$, change variables to get an integral of $e^{-t^2}$2017-02-24
  • 0
    Oh my. Not one, not two, but three useless parameters!2017-02-24

1 Answers 1

2

$\displaystyle I=\dfrac{e^{-bc}}{\sqrt{a-b}}\int_{-\infty}^\infty e^{-x^2}\; dx=\dfrac{e^{-bc}\sqrt{\pi}}{\sqrt{a-b}}$

The integral holds only if $a\gt b$ .