Let $f(t)$ be a primitive polynomial in a finite field, of degree $r$, ${F_q}$ (that is, an irreducible polynomial whose roots in a splitting field have order $q^r-1$). This polynomial can also be viewed as the characteristic polynomial of a linear recurrence. It generates two periodic sequences in $F_q$: the null sequence $(0,0,...)$ and a sequence ("unit sequence" or "impulse-response sequence", as in "Introduction to Finite Fields" of Lidl & Niederreiter) with lenght $q^r-1$. As an example $t^2-t-1=t^2+2t+2$ is primitive in $F_3[t]$. It is the characteristic polynomial of the linear recurrence $x_{n+2}+2x_{n+1}+2x_n=0$ (or $x_{n+2}=-2x_{n+1}-2x_n$, that is $x_{n+2}=x_{n+1}+x_n$) and the sequences generated are $(0,0,...)$ (periodic with period $1$) and $(0,1,1,2,0,2,2,1,0,...)$ (periodic with period $8$). Any other sequence is a cyclic shift of these two.
My question is the following: let $K$ be a field that contains ${F_q}$ and in such a way that $f(t)$, as an element of $K[t]$, is also irreducible. There is a result (6.28 in Finite Fields, of Lidl & Niederreiter) that asserts that every non-null sequence generated by such an $f(t)$, with elements in $K$, is periodic with period equal to $ord(f(t))$ (in this case, $q^r-1$).
Note that these sequences can also be viewed as belonging to $K^r$.
But besides the lenght of these sequences being the same, anything more of interest can be said about these sequences? I know this is this rather vague. What I would like to prove (or disprove) is the following: in $K^r$ all sequences that have $f(t)$ as a characteristic polynomial are non-null (every element of it is non-zero) or alternatively is a multiple of (a cyclic shift) of the unit sequence? Probably I am asking too much: I am asking that, as soon as the sequence has a zero, it must be a multiple of the unit sequence.
Note also that this only concerns polynomials of degree $r \geq 3$ (if $r=2$ this is true).