Question:
A message wants to be sent through a transmitter. There are 6 distinct symbols (Assume A B C D E F). There is also 50 blank spaces given, with at-least 8 spaces between each successful consecutive symbol.
How many ways the message be sent ?
My solution:
There are 6 symbols given, and their order clearly matters.
$\therefore$ 6!
Also, A (1) B (2) C (3) D (4) E (5) F, there are 5 locations in between the symbols. Each consecutive pair of symbol can have at-least 8 spaces in between.
50 (total spaces) - (5(locations) * 8(spaces)) = 10 left over blank spaces that can be placed anywhere.
$\therefore$ $n+r-1 \choose r$ using combinations with repetitions.
n = 5 locations and r = 10 leftover spaces (limiting factor)
$\therefore$ $5+10-1 \choose 10$
Putting everything together we get:
$\therefore$ 6! * $5+10-1 \choose 10$ ways to arrange the symbols and leftover blank spaces.
Logical Question:
Am I right with my logic?

