$P(\frac{4-10}{6} \lt \frac{X-10}{6} \lt \frac{16-10}{6})$
$P(-1 \lt Z \lt 1)$
$(1-\Phi O) - \Phi 0)$
$((\Phi 0)-\Phi 0)$
0,
This can't be correct. I am not sure where I went wrong. This is my first time handling normal random variables.
$P(\frac{4-10}{6} \lt \frac{X-10}{6} \lt \frac{16-10}{6})$
$P(-1 \lt Z \lt 1)$
$(1-\Phi O) - \Phi 0)$
$((\Phi 0)-\Phi 0)$
0,
This can't be correct. I am not sure where I went wrong. This is my first time handling normal random variables.
Your first two steps are good. To compute $$\mathbb{P}(-1 Alternatively, we could note that by symmetry $$\Phi(-1) = 1-\Phi(1),$$
hence $$\mathbb{P}(-1