lei sequence $a_{1},a_{2},a_{3},\cdots,a_{m},b_{1},b_{2},\cdots,b_{n}$ be natural number,and $a_{1} show that：
$$L(m,n)=\sum_{d_{1}|m,d_{2}|n,d_{1}
Show that the number of triplets $(a_{n},b_{n})$ define $L(m,n)=\sum_{d_{1}|m,d_{2}|n,d_{1}
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sequences-and-series
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0Sorry not sure if I understand correctly what is the number of triplets. Could you please clarify? – 2017-03-04
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0for example,if $a_{n}=n, n^2$, $b_{n}=n+1.n+2$,then the number of triplets $(a_{n},b_{n})$ it's $2\times2=4$ – 2017-03-05
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0I don't understand "triplets" either. You say "triplets $(a_n,b_n)$", but $(a_n,b_n)$ is a pair, not a triplet. Your comment above is also confusing. How can $a_n = n, n^2$, when $a_n$ is defined to be a natural number (as opposed to the pair $n,n^2$) – 2017-03-07