Let the function be
$f(x) = x^3 + 2x^2 -8 $
Let the fixed point equation of $f(x)$ be $g(x) = \sqrt{ \dfrac{8}{3+x}} $
How do I should that the equation $g(x)$ is a fixed point equation of $f(x)$?
My solution is to plug in $g(x)$ into $f(x)$.
Numerical Analysis: Fix point equation
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numerical-methods
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0Hint: Wikipedia states "That is to say, c is a fixed point of the function f(x) if and only if f(c) = c. This means f(f(...f(c)...)) = fn(c) = c". – 2017-02-22
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0@HuyVo: Is $g(x)$ written correctly? Maybe $f(x)$ is written incorrectly. – 2017-02-22