How would I go about proving or disproving this statement?
$$\int_{4+a}^{2a+1} \int_{4a+b}^{2b+1} \frac{6}{ {2a}(b^3+1)^{1/4}} \, {db}\,{da}=-\int_{4+a}^{2a+1} -\int_{2b+1}^{4a+b} \frac{6}{ {2a}(b^3+1)^{1/4}} \, {db}\,{da}$$
How would I go about proving or disproving this statement?
$$\int_{4+a}^{2a+1} \int_{4a+b}^{2b+1} \frac{6}{ {2a}(b^3+1)^{1/4}} \, {db}\,{da}=-\int_{4+a}^{2a+1} -\int_{2b+1}^{4a+b} \frac{6}{ {2a}(b^3+1)^{1/4}} \, {db}\,{da}$$