I got the answer "no such $v$ exists" for both exercises. However, I am very surprised, since the $u's$ I have been given seem very nice and arbitrary. I would like to know if I solved them correctly, and if so, what underlying reason makes these seemingly nice functions so hostile?
$1) u(z) = x^3$
Using the Cauchy Riemann equations, we need $3x^2 = v_y$ and $0 = v_x$. The first equation gives us $v(z) = 3x^2y + g_1 (y)$, and the second gives us $v(z) = g_2(y)$. There is no $v(z)$ which satisfies these requirements.
$2) u(z) = x^2+y$
Using the Cauchy Riemann equations, we need $2x = v_y$ and $-1 = v_x$. The first equation gives us $v(z) = 2xy + g_1 (y)$, and the second gives us $v(z) = -x + g_2(y)$. There is no $v(z)$ which satisfies these requirements.