we know that $\pi^2 \int_0^a |f|^2 dx \leq a^2 \int_0^a |f'|^2 dx$ if $f$ is $C^1$ and $f(0)=f(a)=0$. I am interested in is this inequality also valid if $f(0) \neq 0$?
Is Wirtinger's inequality valid on the space if $f$ is non-zero on the boundary?
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functional-analysis
2 Answers
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No. Let $f(x)=1-x$ and $a=1$. Then:
$$\pi^2 \int_0^1 (1-x)^2\ dx =\frac{\pi^2}{3}> \int_0^1 (-1)^2\ dx=1$$
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No. Take $a=1$ and $f(x)=1-x$
Then $\pi^2 \int_0^1 |f|^2 dx =\frac{\pi^2}{3}$ but $ \int_0^1 |f'|^2 dx=1$
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0Great minds think alike? :) – 2017-02-22
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0I agree with you ! – 2017-02-22