If I want to find the probability for a $z$ score of say $1.405$ and my printed normal tables tables only give me $z_{(1.40)}=0.9192$ and $z_{(1.41)}=0.9207$, is it acceptable to do: $z_{1.405}\approx \frac{0.9207+0.9192}{2}=0.91995$?
In this example the three numbers all round to $0.92(2sf)$ but this is not always the case.
In some books the $1.405$ is first rounded up to $1.41$ and hence $z_{1.41}=0.9207$ is taken.
But we know than $z_{1.405}$ is neither of and lies between $0.9192$ and $0.9207$. And although we know that $z_{x}$ does not change linearly with $x$ is it reasonable to make this approximation when no other means are available?
Of course one could check online for more detailed tables or tackle the integration of the probability function for the desired result but if one does not have such options is the method above reasonable?