prove that : $$∠P A K≅∠ MAQ$$
Thank you in advance.
prove that : $∠P A K≅∠ MAQ$
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geometry
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0My thought: $AQMP$ is cyclic. Your thoughts? – 2017-02-22
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0As $AQMP$ is cyclic, $MAQ \cong QPM$, but as $m(AKP) = m(MPA) = \pi/2$, it follows that $PAK \cong QPM$, therefore $MAQ \cong PAK$. – 2017-02-22
1 Answers
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As pointed out, APMQ is cyclic. Therefore $\angle 1 = \angle 2$.
The shaded triangle consists of 3 triangles, and they are similar to each other. Therefore, $\angle 1 = \angle 3$