$f(n+1)=9f(n)+5f(n-1)-9n\times2^{n-1}$
How to solve this? I have problem with $g(n)=-9n\times2^{n-1}$ I can start and calculate $\Delta$ and $x_1$ and $x_2$ but when I get $s_n=c_1\times 1^n+c_2\times5^n + g(n)$. I don't know what after to do.
How to solve this reccurence with g(n)=-9n*2^(n-1)
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discrete-mathematics
recurrence-relations
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1You need to put curly braces around exponents ... too slow ... an edit has been ... – 2017-02-22
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0I get know there is -9n so An+B linear not constant but after system of equations – 2017-02-22
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0Try a transformation $h(n) = g(n)/2^n$ – 2017-02-22
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0Oops... make that $h(n) = f(n)/2^n$ – 2017-02-22