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Enrique is $27$ years younger than Holly. $7$ years ago, Holly's age was $2$ times Enriques age. How old is Enrique now?

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    Between this and [your prior questions](http://math.stackexchange.com/questions/2154910/word-problems-linear-equations) it looks like you are just posting your homework for us to do for you. Please edit to show your efforts and to indicate where you are getting stuck. – 2017-02-21
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    If you show effort, like lulu said, then you shouldn't receive any down votes. Next time, show some effort into your problem(s). – 2017-02-21
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    Unfortunately, lulu, while you are spot on, there always seems to be users who are desperate for rep point and will answer anything. (See the four answers below, as evidence.) – 2017-02-22

4 Answers 4

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7 years ago Holly was still 27 years older than Enrique.

So obviously 7 years ago Enrique was 27. So he's $27+7=\boxed{34}$ years old now.

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    I can't understand this silent downvote. This answer is smarter than the others (including mine). – 2017-02-21
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Let $x$ be Enrique's current age and $y$ be Holly's current age, then you can rewrite your question as a system of equations $$x=y-27$$ $$y-7=2(x-7)$$ Can you solve for $x$?

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Another way to do this is to let $E$ and $H$ be the ages of Enrique and Holly 7 years ago respectively. Therefore, solve the following system of equations: $$\begin{cases} E+27=H \\ H=2E \end{cases}$$ After solving for $E$, just add $E$ by $7$ to get Enrique's current age.

Feel free to comment on your progress, and ask if you have any questions or doubts.

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$$\begin{cases}E+27=H,\\ H-7=2(E-7).\end{cases}$$

$$E+27-7=2E-14,$$

$$E=34.$$