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$$f(x,y)=x \log(y)$$


Partial derivatives: $$f_x(x,y)=\log(y)$$ $$f_y(x,y)=\frac{x}{y}$$


Stationary points:

\begin{cases} f_x(x,y)=\log(y)=0 \\ f_y(x,y)=\frac{x}{y}=0 \end{cases}


Solution: $(0,1)$


Hessian matrix in $(0,1)$:

$$f_{xx} (x,y)=0$$ $$f_{xy}(x,y)=f_{yx}(x,y)=\frac{1}{y}$$ $$f_{yy} (x,y)=-\frac{x}{y^2}$$


$$f_{xx} (0,1)=0$$ $$f_{xy}(0,1)=1$$ $$f_{yy} (0,1)=0$$


$$H_f(0,1)=\begin{pmatrix} 0 \ 1 \\ 1 \ 0 \end{pmatrix} $$


$$\det H_f(0,1)<0$$

$(0,1)$ is a Saddle point


Is it correct?


Thanks!

1 Answers 1

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Yes. Everything is correct. Well done !