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Let $E$ be a Banach space and $T:E\to E^*$ be a linear operator such that

(a) $\langle Tx,x\rangle\ge 0,\,\,\,\,\forall x\in E $, by applying closed graph theorem prove that $T$ is a bounded operator.

(b) $\langle Tx,y\rangle=\langle Ty,x\rangle,\,\,\,\,\forall x,y\in E $, Prove that $T$ is a bounded linear operator.

So far I did the following:

(a) If we can prove that the graph of $T$ is closed then by closed graph theorem $T$ is continuous as well as bounded. Let $\{x_n\}\in E$ be a sequence such that $x_n\to x$ and $Tx_n\to f$, then passing the limit to the inequality

$$\langle T(x_n-y),x_n-y\rangle\ge 0$$

we get

$$\langle f-Ty,x-y\rangle\ge 0,\,\,\,\,\,\,\forall y\in E$$

Therefore by letting $y=x+tz,t\in\mathbb{R},z\in E$ we get the result.

(b) Sorry to bother you that I am stuck. Any help would be highly appreciated. Thanks in advance.

  • 1
    [this](http://math.stackexchange.com/questions/586072/prove-that-a-linea)2017-02-20
  • 1
    Hint: Banach-Steinhaus.2017-02-20

0 Answers 0