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How to calculate the Fourier coefficients, of a given input : $$u(t)=\sum_{k=-\infty}^{+\infty}\overline u_k e^{ik\omega_0t}$$ of this output: $$v(t)=u(t)(1-cos^2(\omega_0t))$$ So how is the mathematical definition of this, maybe started from the definition of Fourier series. So how can I start this ?

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    What's your formula for the fourier coefficient? Does $c_n = \frac{1}{2\pi}\int_0^{2\pi} f(t) e^{2\pi int}dt$ look familiar?2017-02-20
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    Hmmmm I think I have to found $a_0, a_n \ and \ b_n$ or not?2017-02-20
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    Try expanding $1-\cos^2(\omega_0 t)$ into complex exponentials.2017-02-20

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$$v(\Omega)=\frac{1}{2\pi}\int_{-\pi}^{\pi}u(t)e^{{i}\Omega{t}}dt-\frac{1}{2\pi}\int_{-\pi}^{\pi}u(t)\cos^{2}(\omega_{0}t)e^{{i}\Omega{t}}dt=$$ $$=\frac{1}{2}u(\Omega)-\frac{1}{2\pi}\int_{-\pi}^{\pi}u(t)\frac{e^{2i\omega_{0}t}+e^{-2i\omega_{0}t}}{4}e^{{i}\Omega{t}}dt=$$ $$=\frac{1}{2}u(\Omega)-\frac{1}{4}u(\Omega+2\omega_{0})-\frac{1}{4}u(\Omega-2\omega_{0})$$

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    Sorry, but $\Omega$ is instant of what?2017-02-20
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    $\Omega$ is a summation index. You name it $k$2017-02-20