If two six sided die with the numbers $1,0,1,2,3,4$ on each of them are rolled. What is the probability that the product of the numbers on the upmost faces is greater than the sum.
I have an answer key that states the answer to this is $11/36$, but I keep getting $8/36$. What am I missing?
I'm also getting the answer $8/36$, the $8$ cases being:
$(4,4),(3,4),(4,3),(2,4),(4,2),(3,3),(2,3),(3,2)$
The other answer I can see to this problem is to consider the cases where the product is greater or $\textbf{equal}$ to the sum. In this scenario, other two cases come into play:
$(2,2),(0,0)$
But in this scenario the answer would be $10/36$. Anyway, I think the right thing to say is that either your answer key is wrong, or the question was misenterpreted and I'm missing one case.
If 0 on any dice it makes product 0. So not greater than sum.
If 1 on any dice then product with any number is not greater than the sum of 1 and number.
So we left with numbers 2,3 and 4. So these numbers give us 8 cases. You already have. So your answer is correct.