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If $[a,b)$ ($a

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    Consider $f(x)=\sqrt x$ on $[0,1)$ at $x=0$.2017-02-19
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    I will reformulate. Take the open interval $(a,b)$.2017-02-19
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    Do you know the cantor function?2017-02-19
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    I know it is continuous and increasing and has a derivative almost everywhere. Am I right? But does it have a right derivative everywhere?2017-02-19
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    sorry. Please forget the cantor function. That makes thing unnecessarily complicated. Consider $f(x) = \sqrt[3]{x}$ on any open interval containing $0$.2017-02-19
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    thanks. if one allows the right derivative to take on values in the extended real line, then the claim might hold true...2017-02-19
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    I know no useful instance in which one consider $\pm \infty$ as a valid derivative. Notice there is result that a continuous and monotonous function is almost everywhere differentiable.2017-02-19
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    the result says that monotonic functions (not necessarily continuous) are almost everywhere differentiable.2017-02-19

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