For example, find a curve that is tangent to the line $y=2x-3$ at $x = 5$. Is the solution (curve) unique?
How to find a curve that is tangent to a line at a specific coordinate?
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calculus
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0I'm not sure what you mean exactly. If the line is the tangent line at that point, the curve would be found by integrating the line, wouldn't be? – 2017-02-19
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0@Masacroso Oh! That makes much more sense... – 2017-02-19
1 Answers
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The derivative at $x=5$ is $2$. Then the only restriction that our curve must have is that at the point $(5,7)$ it must have instantaneous slope $2$. So the only restriction is that,
$$f(5)=7$$
$$f'(5)=2$$
The solution is not unique.
For example take $f(x)=ax^2+bx+c$ with $f(5)=25a+5b+c=7$ and $f'(5)=2a(5)+b=2$. Two linear equations, 3 unknowns. Thus an infinite amount of solutions just for quadratics, and we can likely find others.
If you want only one solution, looking at what we have above, maybe let $a=1$ so that $b=-8$ and $c=22$.
So one solution is,
$$f(x)=x^2-8x+22$$
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0Got it. Thank you for your guidance. – 2017-02-19
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0You're welcome! – 2017-02-19