If $G$ is a graph with $2k$ vertices, and every vertex of $G$ has degree at least $k$, how can I prove that $G$ has a perfect matching? (I used induction, and I am confused on Induction Conclusion: how can we use $2(k+1)$ vertices to deduce that $G$ is has a perfect matching? Do two new points mean there is a new edge that can be part of the perfect matching?)
even graph with degree k has a perfect matching.
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graph-theory
matching-theory
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0Have you tried consulting https://en.wikipedia.org/wiki/Hall's_marriage_theorem? – 2017-02-17
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0Hall's theorem is not immediately helpful since the graph is not bipartite. – 2017-02-17
1 Answers
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I don't see how to get induction to work: when you match two vertices in a $2k+2$ graph where everything has degree at least $k+1$, what's left is a $2k$-vertex graph with every degree at least $k-1$, which is not good enough.
Hint: can you show that the graph is Hamiltonian? Why is this enough to ensure a perfect matching?