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$MR(x)=4x(x^2+26,000)^{-2/3}$

I'm already lost at the part $2\int u^{-2/3}$ How did they get $6u^{1/3}+C$

a)Find the revenue function

b) What is the revenue from selling 250 ​gadgets? ​

c) How many gadgets must be sold for a revenue of at least ​$50​,000?

Solve for x. (How?)

$6(x^2+26,000)^{1/3}-150=50$

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    Please always include your own attempt at solving the problem. – 2017-02-16

1 Answers 1

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For any $r \neq -1$, $\int x^r dx = \frac{1}{r+1}x^{r+1} + C$. This is just the reverse of the derivative $\frac{d}{dx}x^r = rx^{r - 1}$. Set $r = -\frac{2}{3}$ and you get the integral you're asking about.

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    Thank you, I used that earlier but don't know what I did to get the wrong answer – 2017-02-16