I don't grasp some steps in this quick proof of Cauchy-Schwarz inequality.
Let $\boldsymbol{u}$ and $\boldsymbol{v}$ be two vectors in $\mathbb{R}^n$. The Cauchy-Schwarz inequality states that $$ \boldsymbol{u} \cdot \boldsymbol{v} \leq |\boldsymbol{u}||\boldsymbol{v}| $$
We know that \begin{align} |\boldsymbol{u}+\boldsymbol{v}|^2&=(\boldsymbol{u}+\boldsymbol{v})\cdot (\boldsymbol{u}+\boldsymbol{v})\\ &= \boldsymbol{u}\cdot \boldsymbol{u}+\boldsymbol{v} \cdot \boldsymbol{v} +2\boldsymbol{u}\cdot \boldsymbol{v}\\ &=|\boldsymbol{u}|^2+|\boldsymbol{v}|^2+2\boldsymbol{u}\cdot \boldsymbol{v} \tag{1} \end{align} Using Cauchy-Schwarz, we have $$ |\boldsymbol{u}|^2 +|\boldsymbol{v}|^2+2\boldsymbol{u}\cdot \boldsymbol{v} \leq |\boldsymbol{u}|^2+|\boldsymbol{v}|^2+2|\boldsymbol{u}||\boldsymbol{v}|=(|\boldsymbol{u}|+|\boldsymbol{v}|)^2 \tag{2} $$ So the Cauchy-Schwarz inequality gives $$ |\boldsymbol{u}+\boldsymbol{v}|^2 \leq (|\boldsymbol{u}|+|\boldsymbol{v}|)^2 $$ or $$ |\boldsymbol{u}+\boldsymbol{v}| \leq (|\boldsymbol{u}|+|\boldsymbol{v}|) $$
I don't understand the inequality in equation (2). How can we conclude the inequality? I.e why is $$ |\boldsymbol{u}|^2 +|\boldsymbol{v}|^2+2\boldsymbol{u}\cdot \boldsymbol{v} \leq |\boldsymbol{u}|^2+|\boldsymbol{v}|^2+2|\boldsymbol{u}||\boldsymbol{u}| \quad\text{?} $$
And how is $\boldsymbol{u} \cdot \boldsymbol{v} \leq |\boldsymbol{u}||\boldsymbol{v}|$ equivalent to $ |\boldsymbol{u}+\boldsymbol{v}| \leq (|\boldsymbol{u}|+|\boldsymbol{v}|)$?