0
$\begingroup$

Really hope someone can help me! I've been struggling with this issue the past 5 hours and can't seem to figure out why or simply don't understand the outcome.

I'm solving a cubic equation using the "depressed equation" method and then cardanos' formula. If I solve the cubic equation in my CAS (TI-Inspire) I get one result, but if I solve the depressed equation via cardanos' method, I get a different result. Isn't those two results suppose to be the same (finding the root)?

I get a complex number as the result, but I think I'm suppose to get the real number solution. Am I doing something wrong here?

Thanks in advance Mike

image over calculations

  • 0
    can you give us the complete formulas you used?2017-02-14
  • 1
    All cubics have 3 solutions: 1 real and 2 complex (non-real) solutions, or all 3 solutions are real. I'm guessing the CAS is only showing you one of the 3 possible roots, and your two different inputs are producing 2 different roots (of the 3 possible) to show you as output. I suggest modifying your input to the CAS to show all three solutions in both cases.2017-02-14
  • 0
    http://i.imgur.com/UktNjJc.png I used the Cardanos' formula for depressed equation :)2017-02-14
  • 0
    A bit unsure, but the Cardanos' formula is only for when p & q in the depressed equation are of positive numbers? If so, how do I handle the negative P value I have? (-3.25)2017-02-14

0 Answers 0