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If I have $\cos(x)=-\cos(x+\alpha)$,

can I solve it by doing
$x=-(x+\alpha+2\pi)$ and $x=-(-(x+\alpha+2\pi))$?

It's probably a stupid question but I'm really confused.

2 Answers 2

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Hint:

$\cos(u+\pi)=-\cos u$

and

$\cos x=\cos A\implies x=2m\pi\pm A$

Where $m$ is any integer

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HINT: $$\cos(x)+\cos(y)=2\cos\left(\frac{x-y}{2}\right)\cos\left(\frac{x+y}{2}\right)$$