This is where I am...
$\frac{1-1}{-7-3}=\frac{0}{-10}$
But it doesn't work.
What is the perpendicular bisector of $C (3,1)$ and $D (-7,1)$?
-2
$\begingroup$
geometry
2 Answers
1
A general advise: always take advantage of the specificities of a problem:
Here, if you draw a figure, you will see that your points, being at the same ordinate have, for their perpendicular bissector, a vertical line intersecting the $x$ axis halfway between $-7$ and $3$, thus with equation $x=-2.$
0
Hint: Find the mid point of the line given then use Point Slope Form.
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0Does this work when the perpendicular line doesn't have a slope? – 2017-02-13
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0What do you mean that the line don't have a slope? The line have a slope which is $0$ i.e. $x-\text{axis}$ – 2017-02-13
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0The line segment, sure. But it seems as though your advice is to then use the point-slope form to write down the equation of the line perpendicular to it. – 2017-02-13
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1Sorry that my mistake – 2017-02-13