Find the $n^{th}$ order derivative of $ y=x \log\frac{(x-1)}{(x+1)}$ by using leibnitz's formula of two function
I can not understand that how it is proved, so please somebody help me.I tried but ,I am unable to find the answer.
Find the $n^{th}$ order derivative of $ y=x \log\frac{(x-1)}{(x+1)}$ by using leibnitz's formula of two function
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calculus
real-analysis
1 Answers
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HINT: $log(\frac{x+1}{x-1}) = log|x+1|-log|x-1|$
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1if $x>1$ and $log(\frac{x+1}{x-1}) = log(-x-1)-log(1-x)$ for $x<-1$ In both cases $log(\frac{x+1}{x-1}) = log|x+1|-log|x-1|$ – 2017-02-13