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You have a bag of 36 candies you want to give to your 6 friends. The company that makes the candies guarantees that exactly 6 of the candies in the bag are red, the most delicious color. Anyone who doesn't get a red candy will be so upset that they will stop being your friend! But the candies are in identical wrappings, so you are forced to give each friend 6 candies and hope for the best. What's the probability you lose one or more friends?

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    Not asking the answer but can someone explain how to approach it ? – 2017-02-13
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    You have shallow friends – 2017-02-13

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Hint: First, use the fact that $\mathbb{P}(\text{"you lose one or more friends"})=1-\mathbb{P}(\text{"you don't lose any friend"}).$ Then what is the probability that each friend gets exactly one red candy? Determine the probability $p_i$ for $i$-th friend to get exactly one candy given the fact that the $j$-th friend for $j

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    "Determine the probability pi for i-th friend to get exactly one candy and multiply pi's to get the joint probability. " - you should prove that these are independent – 2017-02-13
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    The probabilities $p_{i}$ are not meant to be independent. What I meant is: determine the probabilities that $i$-th friend gets exactly one candy given that fact that each friend before got exactly one candy as well. I edited the answer. – 2017-02-13