A can do the work in 15 days and B can demolish that work in 20 days. If they work on alternate day starting with A, how many days are required to do the work?
Total unit of work= LCM(15,20)=60 units A can do 4 units B= -3 units( - because B demolishes the work) Now, in 2 days 1 unit work will be completed. I understood till this point. Now, in the solution it has been given that subtract the maximum work from 60 which gives us 56. 1 unit-2days 56 units-112 days hence, total number of days is 113. Help me understand this solution.
