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I have to ptove that $O(n,\mathbb{R})$ is a strong deformation retract of $GL(n,\mathbb{R})$. In order to do this I must check the continuity of the map $GL(n,\mathbb{R})\longrightarrow O(n,\mathbb{R})$ defined by $A=O\cdot S\longmapsto O$ ,where $O\in O(n,\mathbb{R})$ and $S$ is real symmetric and positively defined. How I can check the continuity?

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The matrix $S$ can be explicitly obtained from $A$ as $\sqrt{A^TA}$, where the radical sign means the unique positive-definite square root. So it suffices to show that the map taking a positive-definite matrix to its positive-definite square root is continuous. There are several ways you can do this. For instance, if $B$ is a positive-definite matrix whose spectrum is contained in $(r,R)$ for $0

(Note that a more elementary deformation retraction from $GL(n,\mathbb{R})$ to $O(n,\mathbb{R})$ can be obtained by applying Gram-Schmidt orthonormalization to the columns of $A$. Each step of Gram-Schmidt is easily seen to be continuous and can be interpolated by a homotopy.)

  • 0
    Do you think that there is a moore direct proof?2017-02-12
  • 0
    Possibly, but I don't know one off the top of my head.2017-02-12