A partial order $<$ on a set $A$ has dimension less than n+1 if there exists a sequence of n linear orders {$<_1,.....,<_n$} on $A$ such that:
$\forall\ x,\ y\in A, x Show that a partial order on a set A has dimension less than $n+1$ iff for every finite subset $X\subseteq A$, the restriction of $<$ on $X$ has dimension less than $n+1$. This question is practically begging me to use compactness just by it's phrasing, but the problems is I have NEVER use compactness before in my life, hence I'm stuck after a few steps. Below is my attempt. Compactness theorem: A set of wffs is satisfiable iff every finite subset is satisfiable Attempt: Pick any finite subset $X\subseteq A$. Let $<$ be restricted to X and has dimension less than $n+1$ Fix an $x, y$. Let $<$ be any linear order. Define truth assignment $v$ as follow, $v($<$):= \begin{cases}
T\ \iff x So now I want to mould the assumption I made so that I can say X is satisfiable, but I dont exactly know what it means to be satisfiable in this context. Any help or insights is deeply appreciated. To any veteren of using compactness, it would mean so much if you could share when and how to use compactness in general