The question here is not well worded, especially as a math question. It's possible, however, to guess at what the given data means, and at what tacit assumptions apply in order to get an answer.
A way to interpret things is that, for every $10{,}000$ births, there are $200$ pairs of twins (i.e., $2\%$). Of these, $16$ pairs (i.e., $0.16\%$) are identical twins, so the $184$ other pairs are fraternal. Since identical twins must be of the same sex, there will be $8$ boy-boy twins in that subgroup. For fraternal twins, however, the sex of each twin is presumably independent, so only a quarter of that subgroup, or $46$ will be boy-boy. Thus there are $8+46=54$ boy-boy pairs of twins, of which $8$ are identical, for a probability of $8/54\approx0.148$
(I see Cato posted essentially the same answer moments before me.)