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i was able to solve questions a) and b) but am confused on how to solve this question Show that for any events A and B (with probabilities not equal to 0 or 1), P(A|B) > P(A|B^c) is equivalent to P(B|A) > P(B|A^c).

1 Answers 1

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HINT

Use $P(A \cap B)=P(A|B)*P(B)$ and $P(A) = P(A\cap B) + P(A \cap B^C)$