The question asked "Find the sum of the solutions to $$x^2+4x+1=[x]$$ I tried solving for the sum claiming that $[x]$ was a scalar matrix, however that was incorrect. I'm not sure what $[x]$ means.
The answer was given to be $-2+\sqrt{2}$
The question asked "Find the sum of the solutions to $$x^2+4x+1=[x]$$ I tried solving for the sum claiming that $[x]$ was a scalar matrix, however that was incorrect. I'm not sure what $[x]$ means.
The answer was given to be $-2+\sqrt{2}$
$[x]$, in this context, seems to denote the Floor Function. The modern notation is $\lfloor x \rfloor$, but some textbooks still use the archaic notation for the floor function, which is $[x]$ as in the question. Your quadratic can be solved by bounding $x$ using a preexisting bound on the floor function, namely $$x \ge [x] > x-1$$ So this gives us a bound on $x$, which in turn restricts $[x]$. Can you take it from here?
Basically you have to solve at first $ x \leq x^2 + 4x + 1 < x+ 1 $