$\int \frac{2dx}{(x-2)(x-1)x}$
Any help with how to solve this will be appreciated.
Solving the integral $\int \frac{2dx}{(x-2)(x-1)x}$
0
$\begingroup$
integers
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1What method do you think will apply? You must have worked with this type of expression before. How do you "simplify" such an expression for the purpose of integrating it? – 2017-02-04
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0Converting the expression into a sum! Pretty easy, it just didn't click before. – 2017-02-04
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1Typically, you will get more help and more upvotes if you indicate what you've tried, and show where you get stuck. – 2017-02-04
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1Thanks, I'll keep that in mind! – 2017-02-04
1 Answers
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Partial fraction expansion
$$\frac{2}{(x-2)(x-1)x}=\frac{1}{x}-\frac{2}{x-1}+\frac{1}{x-2}$$
The rest is easy.
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2Thankyou! It will take some time for the right approach to click right away i guess. – 2017-02-04