Find the solution to the Integral Equation:
$\phi(x)=x+\int _0^x \sin (x-t)\phi(t) dt $
The solution is given as $x+\dfrac{x^3}{3!}$.
My try:
$K(x,t)=\sin (x-t)=K_1(x,t)$;
$K_n(x,t)=\int _t^x K(x,z) K_{n-1}( z,t) dz$;
I got $K_2(x,t)=\sin(-x-t)-\sin (x-3t)-(x-t)\cos (x-t)$.
So it's getting difficult.I am appearing for an exam where the time given will be small for this 1 mark question.
Is there any easy way to do this?