(a+c)(a+b')(a'+b+c')
i used DeMorgan to simplify and got a'c'+a'b+ab'c, how can i simplify further?
Find the complement of the expression
0
$\begingroup$
logic
boolean-algebra
1 Answers
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What you got doesn't simplify any further!
If you were to do a K-map you'll find that your expression a'c'+a'b+ab'c is the 'simplest' one.