What do the differentials $dx$ and $dy$ do in line integrals (path integrals)?

Question

I think that using the arc length differential $ds$ in a line integral finds the area like in https://en.wikipedia.org/wiki/File:Line_integral_of_scalar_field.gif, but I cannot imagine what the area using $dx$ or $dy$ is.

Sometimes the question asks "Evaluate

a) $$\int_C xy^2\,dx$$ b) $$\int_C xy^2\,dy$$ c) $$\int_C xy^2\,ds$$

where the path $C$ is defined by $x=4\cos(t)$, $y=4\sin(t)$, $0\leq t\leq \pi/2$."

I know how to evaluate these, but what do they mean geometrically? Specifically, a) and b) since their differentials are $dx$ and $dy$.

Answer 1

The integrals in (a) and (b) are components of the line integral of a vector field. For example, the line integral of the vector field $F(x,y)=(xy^2,x^2y)$ can be written as $$ \int_C F(\mathbf{r}) \cdot \,d\mathbf{r} = \int_C xy^2 \,dx + x^2y \,dy $$ where $$ \int_C xy^2 \,dx = \int_a^b x(t)y(t)^2 x'(t) \,dt. $$ The Wikipedia "Line integral" article has a gif depicting the line integral of a vector field, but there really isn't any geometric meaning to the individual components of this integral.