1
$\begingroup$

Is the sum $$\sum_{n=1}^\infty \frac{\sqrt{n} - \sin \frac{1}{\sqrt{n}}}{n}$$ convergent?

  • 0
    what does $\sqrt{-}$ mean?2017-02-03
  • 0
    I'd like to edit it, but cannot. It should be $\sqrt{n} - $. The correct formula is $\sum \frac{\sqrt{n}-\sin{\frac{1}{\sqrt{n}}{n}$.2017-02-03
  • 0
    why can't you edit it? I can do it for you2017-02-03
  • 0
    Have no idea..it's correct now, thanks!2017-02-03
  • 0
    Divergent: Comparison test.2017-02-03

1 Answers 1

3

Hint $$\frac{\sqrt{n} - \sin \frac{1}{\sqrt{n}}}{n}\geq\frac{\sqrt{n} - \frac{1}{\sqrt{n}}}{n}=\frac{n-1}{n\sqrt{n}}\geq\frac{n-\frac{n}{2}}{n\sqrt{n}}=\frac{1}{2\sqrt{n}}$$