A ladder rests against the top of a perpendicular wall of a building and makes an angle of $73^{\circ}$ with the ground. If the foot of the ladder is $2$ m from the wall.
Calculate:
- The height of the building,
- The length of the ladder
ladder rests against the top of a perpendicular wall
-4
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trigonometry
2 Answers
2
Hint: Let The height of the building be $x$ m and The length of the ladder be $y$ m.
Then apply that $\cos \theta$ is base/hypotenuse and $\tan \theta$ is perpendicular/base.
Here $\theta = 73^{\circ}$.
2
In following diagram.
Let AB length of the ladder. BC length of the wall of building and AC = 2m distance b/w foot of the ladder and wall.
And $\theta = 73°$
$\tan \theta = \frac{BC}{AC}$
Put values and find BC.
$\cos \theta = \frac{AC}{AB}$
Put values and find AB.