Number of ways in which $8$ people can be seated in a row, if these are $4$ married couples and each couple must sit together ?
I got $4!*2^4$, but I don't have an answer for this.
Have I got this one right ?
Number of ways in which $8$ people can be seated in a row?
1
$\begingroup$
combinatorics
permutations
combinations
2 Answers
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Yes your solution is right.
We have $2^4$ to make each pair sit and then 4! to arrange pairs.
1
First arrange 4 pairs perform 4!, then interchange of male and female within pair can occur in 2 ways, here there are 4 pairs so you have to multiply 4! with 2*2*2*2, each 2 for each pair