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Given $P(A|B) = x$, what can you say about $P(\overline{A}|B)$?

Can we say $1 - x$?

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    Possible duplicate of [Negation of Bayes' theorem.](http://math.stackexchange.com/questions/583266/negation-of-bayes-theorem) – 2017-02-13
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    The proposed duplicate is a fairly circuitous presentation of ideas at best, starting with an incorrect statement of conditional probability (or of Bayes' Theorem, hard to say). I don't think it makes a compelling duplicate. – 2017-02-14

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Yes we can. The same question is answered in this answer.

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    If that answers this question as well, you should flag this one as a duplicate. – 2017-02-02